tolong dong...besok dikumpul...mksh
Luas Persegi Panjang
= P × L
(panjang) × (lebar)
Maka,
[tex]l uas= p \times l \\ \\ = 20 \frac{1}{3} \times 16 \frac{2}{5} \\ \\ = \frac{61}{3} \times \frac{82}{5} \\ \\ = \frac{5.002}{15} = 333 \frac{7}{15} {m}^{2} [/tex]
Jadi luas sawah pak Beni adalah 333 7/15 meter²
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